This is an old revision of this page, as edited by Toolie (talk | contribs) at 01:20, 22 March 2004. The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.
I'll edit this some time...
sin x cos x = tan x {\displaystyle {\sin x \over \cos x}=\tan x}
x 2 5 = x 2 / 5 {\displaystyle {\sqrt[{5}]{x^{2}}}=x^{2/5}}
x 4 8 = x 4 / 8 = x 1 / 2 = x {\displaystyle {\sqrt[{8}]{x^{4}}}=x^{4/8}=x^{1/2}={\sqrt {x}}}
x 3 + 9 x 2 = 9 x + 81 {\displaystyle x^{3}+9x^{2}=9x+81}
x 3 + 9 x 2 − 9 x − 81 = 0 {\displaystyle x^{3}+9x^{2}-9x-81=0}
( x − 3 ) ( x + 3 ) ( x + 9 ) = 0 {\displaystyle (x-3)(x+3)(x+9)=0}
x = 3 o r x = − 3 o r x = − 9 {\displaystyle x=3orx=-3orx=-9}
d y / d x = ( 3 x 3 − ( x + 2 ) ( 1 / 2 ) ) / ( x − 4 ) {\displaystyle dy/dx=(3x^{3}-(x+2)^{(}1/2))/(x-4)}
∫ 1 5 1 ( x − 1 ) 1 / 2 d x {\displaystyle \int _{1}^{5}{\frac {1}{(x-1)^{1/2}}}\,dx}
[ 2 ( x − 1 ) 1 / 2 ] {\displaystyle [2(x-1)^{1/2}]}
[ 2 x − 1 ] {\displaystyle [2{\sqrt {x-1}}]}
[ 2 ( 5 ) − 1 ] − [ 2 ( 1 ) − 1 ] {\displaystyle [2{\sqrt {(5)-1}}]-[2{\sqrt {(1)-1}}]}
4 − 0 {\displaystyle 4-0}
0 {\displaystyle 0}