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y = 2x3 - 3x2 - 3x + 2 = 2(x - ½)3 - 4½(x - ½) = (½)2(2x - 1)[(2x - 1)2 - 32] = 0
Selected cubic polynomial, in my opinion, is not characteristic since it easily can be reduced into depressed quadratic one due to x1 = b/3a = -3/6 = ½ that leads up to
2qQ = 9abc - 27a2d - 2b3 = 9*2*(-3)*(-3) - 27*22*2 - 2*(-3)3 = 0 and pP = b2 - 3ac = 27
y = x3 - 2x2 - x + 2 = (⅓)3[(3x - 2)3 - 21(3x - 2) + 20] = 0 and
2qQ = 9abc - 27a2d - 2b3 = 9*1*(-2)*(-1) - 27*12*2 - 2*(-2)3 - 20 ≠ 0 and pP = b2 - 3ac = 7
http://en.wikipedia.org/wiki/Talk:Cubic_function#Chebishew_radicals_-_inconsistency_and_replacement
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