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희원이~ 그 SAT문제 푸는 방법이야
n = 1 k {\displaystyle n={1 \over k}}
1 − k 1 − n {\displaystyle {1-k \over 1-n}}
= 1 − k 1 − 1 k = 1 − k k k − 1 k {\displaystyle ={1-k \over 1-{1 \over k}}={1-k \over {k \over k}-{1 \over k}}}
= k ( 1 − k ) k − 1 {\displaystyle ={k(1-k) \over k-1}}
= k ( 1 − k ) − ( 1 − k ) {\displaystyle ={k(1-k) \over -(1-k)}}
= − k {\displaystyle =-\ k}
