1812 Virginia gubernatorial election
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The 1812 Virginia gubernatorial election was held on 30 November 1812 in order to elect the Governor of Virginia. Incumbent Democratic-Republican Governor of Virginia James Barbour won re-election in the Virginia General Assembly as he ran unopposed.[1]
General election
[edit]On election day, 30 November 1812, Democratic-Republican nominee James Barbour easily won re-election as he ran unopposed. Barbour was sworn in for his first full term on 1 December 1812.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | James Barbour (incumbent) | 1 | 100.00 | |
| Total votes | 1 | 100.00 | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Gov. James Barbour". nga.org. 13 January 2018. Retrieved 18 May 2023.
- ^ "VA Governor". ourcampaigns.com. 10 February 2013. Retrieved 18 May 2023.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
- ^ "Virginia 1812 Governor". elections.lib.tufts.edu. 18 December 1812. Retrieved 18 May 2023.
Categories:
- 1812 Virginia elections
- Virginia gubernatorial elections
- 1812 United States gubernatorial elections
- November 1812 events
- 1812 elections
- 1812 elections in North America
- 1812 elections in the United States
- 1812 in Virginia
- Indirect elections
- Single-candidate elections
- Government of Virginia
- 1810s in Virginia
- 1810s Virginia elections
- United States gubernatorial elections in the 1810s