User:Erutuon/Math

• formula for area of eq. triangle: $s^{2}{\sqrt {3}} \over 4$
• side (s): $4{\sqrt {3}}$

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$(4{\sqrt {3}})^{2}{\sqrt {3}} \over 4$

$4^{2}\times 3\times {\sqrt {3}} \over 4$

$16\times 3{\sqrt {3}} \over 4$

$4\times 3{\sqrt {3}}$